![]() ![]() void timerStart( QTimer* timer, int timeMillisecond )Ĭonnect( timer, SIGNAL( timeout() ), this, SLOT( noRespFrmServer( ) ) ) Ĭonnect( timer, SIGNAL( destroyed( timer ) ), this, SLOT( stopTimerbeforeTimeout( ) ) ) Īlso in timerStop function I have tried to emit destroyed signal but I got response that it fails to connect. I have used blockSignals ( true ) as well and it doesnt work. But whatever is the case it always emit timeout signal. But if condition is false within specified time then its allright to emit signal timeout(). ![]() IF condition is true then I stop timer and dont want timeout signal to emit or execute connnected slot. ![]() Please, consider that: An application which is under heavy load which causes significant delays of timeout signal emitting is probably not able as well to handle timeout events which are emitted by another thread in time.I have started Timer to wait for certain condition to be true. IMHO, I wouldn't recommend this unless there is a good reason to do so. I considered it for a moment to adapt my sample respectivley but soon realized the necessary effort and stopped. It influences OutSystems applications simple and advanced queries, as well as the entity actions (Create, Update, Get, GetForUpdate and Deleted). ![]() to be done through signals (with Qt::QueueConnection). This SQL Query timeout defines the maximum amount of time that an SQL statement can take to be fully executed, and the resulting dataset be returned to the calling application.to happen before starting the thread or.Moving the QTimer to a different thread would add a lot of overhead. G++ -o testQTimerStartStop.exe testQTimerStartStop.o -lQt5Widgets -lQt5Gui -lQt5Core -lGL -lpthread I/usr/lib/qt5/mkspecs/cygwin-g++ -o testQTimerStartStop.o isystem /usr/include/qt5 -isystem /usr/include/qt5/QtWidgets -isystem /usr/include/qt5/QtGui -isystem /usr/include/qt5/QtCore -I. G++ -c -fno-keep-inline-dllexport -D_GNU_SOURCE -pipe -O2 -Wall -W -D_REENTRANT -DQT_NO_DEBUG -DQT_WIDGETS_LIB -DQT_GUI_LIB -DQT_CORE_LIB -I. TestQTimerStartStop.pro: SOURCES = īuild and run: $ qmake-qt5 testQTimerStartStop.pro QObject::connect(&qBtnStart, &QPushButton::clicked, A network parameter related to an enforced event designed to occur at the conclusion of a predetermined elapsed time. In telecommunications and related engineering (including computer networking and programming), the term timeout or time-out has several meanings, including. QObject::connect(&qEditTimer, (void (QSpinBox::*)(int))&QSpinBox::valueChanged, Network timeout preventing a Web browser from loading a page. tValue(qEditTimer.value() - 1) // count down QObject::connect(&qTimer, &QTimer::timeout, I somehow have the feeling that OP is about to “over-engineer” what could be actually quite simple. MainWindow::MainWindow(QWidget *parent) : Void operator=(Singleton const&) = delete īytes_timer_.moveToThread(QThread::currentThread()) Įxplicit MainWindow(QWidget *parent = nullptr) I should also note that this Singleton class object is running inside of a QThread. For simplicity's sake we can assume that OtherSingleton has the same structure. For the life of me, I cannot figure out why "timeout" is never being printed (indicating that the event is being triggered). If I try to print QTimer's remaining time it reads -1. The connect call is succeeding, the timer is active, and I get no QTimer complaints on the console. A signal/slot connection (with the signal being the QTimer timing out and the slot being a lambda function which makes a call to another Singleton class) is not working. I am trying to create an event that gets fired off every n seconds in my Singleton worker. ![]()
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